2.6:-
A Compound contains 61%
Cashon,
11.88% hydrogen and 27:12 % oxygen
Its molecular max is 118. What
ase its empirical and molecular
formulas
3.
Answers
Answer: An organic compound contains 69.77% carbon, 11.63% hydrogen, and rest oxygen. The molecular mass of the compound is 86.
%O= 100−(69.77+11.63)=18.60
Simple atomic ratio C:H: O=
12
69.77 :
1
11.63
:
16
18.6
=5.88:11.63:1.16=5:10:1
The empirical formula is C
5
H
10
O
Empirical formula mass =5×12+10×1+1×16=86. It is equal to the molecular formula mass. Hence, the molecular formula is the same as the empirical formula.
It does not reduce Tollens reagent. Hence, it is not an aldehyde
It forms an addition compound with sodium hydrogensulphite.
Hence, it contains a carbonyl group.
It gives a positive iodoform test.
Hence, it is a methyl ketone
On vigorous oxidation, it gives ethanoic and propanoic acid.
Hence, it is 2-pentanone.
CH
3
COCH
2
CH
2
CH
3
O
Vigorous
CH
3
CH
2
COOH+CH 3 COOH