Question

= 2.6 atm,
For the reaction N, (g)+ 3H2(g) + 2NH (8), equilibrium pressures are Pv,
PH
= 5.6 atm, and Pia, =1.2 atm. Calculate the Gibb's free energy of the reaction at a
temperature of 298K.​

Answer 1

Explanation:

∆G = -RT ln Keq

= - 8.314 × 298 ln [ {( 2.6)²} ÷ { (5.6) × (1.2)³}]

= -8.314 × 298× ln (0.698)

= - 8.314 × 298 × - 0.3587

=888.725 jule