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If a and B are the zeroes of the polynomial p(x) = x2 - p(x + 1) – c such that
(a + 1) (B + 1) = 0, the c =
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given (a+1)(b+1)=0
p(x)=x2-p(x+1)-c
x2 - px - p -c
x2 - px -( p+c)
as per question
(a+1)(b+1)=0
= ab + a +b +1 =0 ~eq 1
a and b are the zeroes of the polynomial so
(a+b)= -(-p)=p.
ab= -p+c
putting these values in eq 1
-p +c +p + 1=0
c + 1=0
c = -1
hope it helps
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