Question

2:6
ñ 12 men can de a work in a days while tout
can do the same work in 18 days In how mory
days 4ment 6 women together can do the some
12x to
7
nx 3 x to
3.2​

Answer 1

Answer:

Efficiency of 12 men and 18 women = 1/10th part of work per day

Efficiency of 1 man and 18/12 woman = 1/120 th part of work per day

Efficiency of 3 men and 18 women =1/12 th part of work per day

Efficiency of 1 man and 18/3 woman = 1/36 th part of work per day

Efficiency of (18/3 -18/12) women = (1/36 -1/120)th part of work per day

Efficiency 54/12 =(10 -3)/360th part of work per day

Efficiency of 1woman = 7/360×12/54 th part of work per day

Efficiency of 1 woman = 7/(30×54)

Efficiency of 18/12 women = 7/(30×54)×18/12= 7/90×12 th part of work per day

Efficiency of 1 man = 1/120 - 7/90×12 =1/540

Efficiency of 2 men = 2/540 th part of work per day

Efficiency of 3 women = 7×3/30×54 = 7/540 th part of work per day

Efficiency of 2 men and 3 women = 9/540 th part of work per day

Total work = 540/9 days = 60 days