2.) 6-x-x²
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Step-by-step explanation:
-x^2-x+6 = 0
- (x^2+x-6 ) =0
- ( x^2 + 3x-2x -6)=0
- [x ( x +3 ) - 2 ( x + 3)] =0
- [ (x-2) (x+3) ] =0
-1 [ (x-2) (x+3) ] =0 { we can write -1 as the value doesn't changes }
(x-2) (x-3) = 0/-1
(x-2) (x+3) = 0
x=2. x=-3
hope it helps you
Answered by
1
have a nice day dear keep on answering
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