2.63' 2.56' 2.42' 2.71' 2.80 what is the absolute error and percentage error
Answers
Answer:
The mean period of oscillation will be
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11sec
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)Therefore T=2.6±.1s
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)Therefore T=2.6±.1srelative error or percentage error is given by
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)Therefore T=2.6±.1srelative error or percentage error is given by=0.1/2.6*100
The mean period of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe errors in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)Therefore T=2.6±.1srelative error or percentage error is given by=0.1/2.6*1004%.
Explanation:
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