Question

2.66x coin kg
S&H
AAA COLLEGE OF ENGINEERING & TECHNOLOGY
TO DETE
CALCULATION:
948 7W KE.
Mass of the circular disc (M)
2
Length
7.5x6 meter
Radius of the circular disc (R)
kg m
The moment of Inertia of the disc 1 =
MR?
2
x 56. 85x20 - 4
948x10-3
948x 20 -3x (7.5) 10m 942x10
5. 83 x 10.03
meter
Closest distance between suspension wire and the centre of the mass(da) = 3X0
sec
=
Farthest distance between suspension wire and the centre of the mass(dz) = 4xco meter
Time period without any mass placed on disc (T)
= 3.3
Time period with masses placed on disc at a distance d (T1)
3. A sec
Time period with masses placed on disc at a distance dz(T2) in sec
= 3.5
sec
s
= 20 X 10
kg
Given Mass
2
2T’m (d, -d)
T2-T
kg m
The moment of inertia of the disc with masses = 1, =​

Answer 1

Answer:

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Explanation:

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