Question

х²+ 6x - 16 using suitable identities
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Answer 1

Answer:

${x}^{2} - 8x + 2x - 16 \\ x(x - 8) + 2(x - 8) \\ (x + 2)(x - 8) \\ x = - 2 \\ x = 8$

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

X²+6x-16

The above equation is in the of a quadratic equation so,we factorise it to find roots.

How to factorise..??

x²+6x-16

The coefficient of x² is 1

6x is a middle term and its coefficient is 6

and the constant" is +3

Step-1 : Multiply the coefficient of x² by the constant -16×1= -16

Step-2 : Find two factors of -16 whose sum is equal to the coefficient of the middle term, which is 6.

No such factors be found So,we use quadratic formula:

x=-b±√b²-4ac÷2

here,a= 1,b= 6 & c= -16

x= -6±√6²-4(1)(-16)/2

x=-6±√36-(-64)/2

x= -6±√36+64/2

x=-6±√100/2

Here,the discriminant b²-4ac is >0

So,it have two real roots

x= -6±10/2

x= 4/2 or x= -16/2

x= 2 or x= -8

Hence , the roots are x= 2 or x= -8.