Question

2/7+(-13/20)+(-11/14)+3/10
Please help me its urgent ​

Answer 1

★ How to do :-

Here, we are given with four fractions to add and find out the correct answer of this. So, here we are going to add these fractions as the same method as adding the whole numbers. But, there is a small change. If the given fractions have different denominators in them, first we should convert them into like fractions or make the denominators same. The method of taking LCM of denominators is very important step. After obtaining the like fractions, we should add only the numerators. So, let's solve!!

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➤ Solution :-

${\tt \leadsto \dfrac{2}{7} + \dfrac{(-13)}{20} + \dfrac{(-11)}{14} + \dfrac{3}{10}}$

Convert them into like fractions by taking the LCM of the denominators.

LCM of 7, 20, 14, 10 is 140.

${\tt \leadsto \dfrac{2 \times 20}{7 \times 20} + \dfrac{(-3) \times 7}{20 \times 7} + \dfrac{(-11) \times 10}{14 \times 10} + \dfrac{3 \times 14}{10 \times 14}}$

Multiply the numbers in numerators and denominators to get the like fractions.

${\tt \leadsto \dfrac{40}{140} + \dfrac{(-21)}{140} + \dfrac{(-110)}{140} + \dfrac{42}{140}}$

Now, arrange all the numerators in only one fraction and add all of them to get the answer.

${\tt \leadsto \dfrac{40 + (-21) + (-110) + 42}{140} = \dfrac{(-49)}{140}}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{(-49)}{140} = \pink{\underline{\boxed{\tt \dfrac{(-7)}{20}}}}}$

$\Huge\therefore$ The answer obtained while simplifying is ${\tt \dfrac{(-7)}{20}}$

Answer 2

-17/20 is your answer for your question