Question

2/√7-√3 rationalize
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Answer 1

Answer:

2/√7-√3.

Rationalising denominator of √7-√3 is √7+√3.

Multiply numerator & denominator by √7+√3.

2/√7-√3×√7+√3/√7+√3.

2(√7+√3)/(√7)²-(√3)². (Because (a-b)×(a+b)=a²-b² where a=√7 & b=√3).

2√7+2√3/7-3. (Because √ & ² will cancel).

2√7+2√3/4.

I think this is your answer.

Answer 2

Answer:

( √7 + √3 ) / 20

Step-by-step explanation:

2 / √7-√3

= [ 2 ( √7 + √3 ) ] / ( √7 - √3 ) ( √7 + √3 )

= [ 2 ( √7 + √3 ) ] / ( √7 )^2 - ( √3 )^2

= [ 2 ( √7 + √3 ) ] / ( 49 - 9 )

= [ 2 ( √7 + √3 ) ] / 40

= 2 ( √7 + √3 ) / 40

Divide, 2 on both numerator and denominator,

= ( √7 + √3 ) / 20