-2/7,m,7/2(m+2)....are in g.p find the value of "m"??????????
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-2/7 , m , 7/2(m+2) in G.P
⇒ If a , b ,and c in G.P. ⇒ ac = b²
Therefore, -2/7 x 7/2 (m+2) = m² ⇒ m² = -m-2 ⇒ m² + m+2 = 0
⇒ From Shridharcharya rule : m = -1 +- √(1)² - 8 / 2 = -1-+√7i/2
In case : 2/7 , m , 7/2(m+2) in G.P.
⇒ 2/7 x 7/2(m+2) = m²
⇒m² = m+2 ⇒ m² - m - 2 = 0 ⇒ m²-2m +m -2 = 0
⇒ (m-2)(m+1) = 0 ⇒ m = -1 , 2
So answer depends upon your question.
⇒ If a , b ,and c in G.P. ⇒ ac = b²
Therefore, -2/7 x 7/2 (m+2) = m² ⇒ m² = -m-2 ⇒ m² + m+2 = 0
⇒ From Shridharcharya rule : m = -1 +- √(1)² - 8 / 2 = -1-+√7i/2
In case : 2/7 , m , 7/2(m+2) in G.P.
⇒ 2/7 x 7/2(m+2) = m²
⇒m² = m+2 ⇒ m² - m - 2 = 0 ⇒ m²-2m +m -2 = 0
⇒ (m-2)(m+1) = 0 ⇒ m = -1 , 2
So answer depends upon your question.
jing:
please check the common ratio...
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