2) 7 necklaces having equal number of beads in each are made
from 756 beads. How many beads are needed to make 15 such
necklaces ?
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! So this is a case of circular permutation. While dealing with this type of problems, we consider the circle to be placed in free space i.e it is symmetric when viewed from and point around it. So to break the symmetry we first fix one of the beads.
Here I am taking a red bead. Now we are left with 4 red and 2 blue beads.
6 beads can be placed in 6! Ways as 1st place will have 6 possibilities, 2nd place will have 5 possibilities and so on which gives
6*5*4*3*2*1 = 6!
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