Question

[(2/7)power4 × (49/8) power 4 ] ÷[(343/64) (-1)]


please help to solve this problem please ​

Answer 1

Step-by-step explanation:

$( {\frac{2}{7} })^{4} \times ({ \frac{49}{8} })^{4} \div (\frac{343}{64} \times ( - 1)) \\ = {(\frac{2}{7} \times \frac{49 }{8} )}^{4} \div ( - \frac{343}{64} ) \\ = {( \frac{7}{4}) }^{4} \div ( - \frac{343}{64} ) \\ = \frac{ {7}^{4} }{ {4}^{4} } \times ( - \frac{64}{343} ) \\ = (\frac{7 \times 7 \times 7 \times 7}{4 \times 4 \times 4 \times 4} ) \times ( - \frac{64}{343} ) \\ = - \frac{7 \times 7 \times 7 \times 7 \times 64}{4 \times 4 \times 4 \times 4 \times 343} \\ = - \frac{7}{4}$

The answer is -7/4