Question

2.746 g of a compound on analysis gave 1.94 g of silver, 0.268 g of sulphur and 0.538 g of oxygen. Find the empirical formula of the compound. ​

Answer 1

Answer:

Question:-

2.746 g of a compound on analysis gave 1.94 g of silver, 0.268 g of sulphur and 0.538 g of oxygen. Find the empirical formula of the compound.

Answer:-

$n_{ag} \implies \frac{1.94}{108} = 0.018$

$h_{s} \implies \frac{0.268}{32} = 0008$

$h_{o} \implies \frac{0.538}{16} = 0.033$

$Ag:S:O= 0.018 : 0.008 : 0.033$

$= 2: 1 : 4$

$\boxed {Ag_{2} So_{4}}$

Answer 2

Step-by-step explanation:

$nAg \: = \frac{1.94}{108} = 0.018 \\ hs \: = \frac{0.268}{32} = 0008 \\ h0 = \frac{0.538}{16} = 0.033 \\ ag \: s \: 0 = 0.018: \: 0.008: \: 0.033 \\ 2: \: 1: \: 4 \\ Ag²So⁴$