Question

2-7x 3 +7x 1-5x 4 +5 x
answer fast as u can..plz...!!​

Answer 1

Answer:1/2

Step-by-step explanation:

1−5x

2−7x

​

=  

4+5x

3+7x

​

 

Applying Alternendo,

⇒  

3+7x

2−7x

​

=  

4+5x

1−5x

​

 

Now applying Componendo and Dividendo,

⇒  

(2−7x)−(3+7x)

(2−7x)+(3+7x)

​

=  

(1−5x)−(4+5x)

(1−5x)+(4+5x)

​

⇒  

−1−14x

5

​

=  

−3−10x

5

​

 

⇒−1−14x=−3−10x

⇒14x−10x=3−1

⇒4x=2

⇒x=  

4

2

​

=  

2

1

​

Answer 2

Applying Alternendo,

⇒

3+7x

2−7x

=

4+5x

1−5x

Now applying Componendo and Dividendo,

⇒

(2−7x)−(3+7x)

(2−7x)+(3+7x)

=

(1−5x)−(4+5x)

(1−5x)+(4+5x)

⇒

−1−14x

5

=

−3−10x

5

⇒−1−14x=−3−10x

⇒14x−10x=3−1

⇒4x=2

⇒x=

4

2

=

2

1

$hope \: it \: helpful$