2+8+14+---------- n terms =3n^2-n prove by induction
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Step-by-step explanation:
let p(m) be the given statement where m is any natural number.
then,clearly p(1) is true as
p(1):
3(1)²-1
=>2
let us assume that p(k) is true where k is a natural number.i.e,
2+8+14+...+(2+(k-1)6)=3k²-k
now by induction,p(k+1) should also be true and 2+6k is the next term..
p(k+8):
2+8+14+..+(2+(k-1)6)+(2+6k)=3(k+1)²-(k+1)
LHS:
3k²-k+(2+6k)
3k²+6k+3 -k-1
3(k+1)²-(k+1)
which is RHS .....
thus,p(m) is true for all m where m is a natural number..
.
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