Chemistry, asked by sushmadeotale2001, 9 months ago

2
8. Fish generally needs o, concentration in
water at least 3.8 mg/L for survival. What
partial pressure of O, above the water is
needed for the survival of fish? Given the
solubility of O, in water at 0°C and 1 atm
partial pressure is 2.2 * 10-3 mol/L (0.054
atm)​

Answers

Answered by dhvaniltanti
0

Answer:

Explanation:

Given, required solubility of oxygen gas for the survival of marine species=4mg/L

We know 1 mole of oxygen =32g of oxygen

0.004g of O  

2

​  

=125×10  

−6

mol/L

Now we know initial pressure above water = 1 atm

Also given,

Initially solubility of O  

2

​  

 gas in water at 1 atm =2.21×10  

−3

mol/L

Now,we know according to Henry's law of partial pressure.

Solubility of gas is directly proportional to partial pressure of that gas over liquid.

S∝P

S  

2

​  

 

S  

1

​  

 

​  

=  

P  

2

​  

 

P  

1

​  

 

​  

 

125×10  

−6

 

2.21×10  

−3

 

​  

=  

P  

2

​  

 

1

​  

 

Answered by rockstar2019
2

answer in attachment.

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