2.8 of calcium oxide prepared by heating limestone was found to contain 0.8g of oxygen. When 1.0g of oxygen is treated with calcium 3.5g of calcium oxide was obtained . Show that the results illustrates the law of definite proportion
Answers
Answer:
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Law of definite proportion states that a given compound always contains exactly the same proportion of elements by weight.
Case I-
2.8 g of CaO contains 0.8 g of oxygen.
Thus, mass of calcium in CaO = 2.8 – 0.8 = 2 g
Ratio of mass of calcium to oxygen = 2/0.8=2.5
Case II-
3.5 g of CaO contains 1 g of oxygen.
Thus, mass of calcium in CaO = 3.5 – 1 = 2.5 g
Ratio of mass of calcium to oxygen = 2.5/1=2.5
Therefore, according to the above given definitions and the results we obtained we can say that the given data illustrates the law of definite proportions.
Answer:
Explanation:
Law of definite proportion states that a given compound always contains exactly the same proportion of elements by weight.
Case 1: Ca2.8g O0.8g ⟹1g of O reacts with =0.82.8=3.5g of CaO
Case 2: 3.5g 1g⟹1g of O reacts with 3.5g of CaO
Ratio of O reacting with Ca to form CaO is 1:1.
Hence results illustrate the law of definite proportion.