Question

-2.8 sin (π/6(x – 12)) + 16 = 16,
0 ≤ x ≤ 2π​

Answer 1

Answer:

x= 0 , 6

Step-by-step explanation:

-2.8 sin(π/6(x-12))+16=16 , 0≤x≤2π

=> -2.8sin( πx/6 - 2π) = 0

=> + 2.8 sin(2π - πx/6) = 0

=> - 2.8sin(πx/6)= 0

=> sin(πx/6)= 0

=> πx/6 = 0 , or πx/6= π , or πx/6 = 2π

=> x= 0 , or x= 6. ,. or x= 12

=> but value of x not more than 2π=> x≠12