Question

(2)
8. The length of altitude of an equilateral triangle of side 8cm is.
(A) √3 cm
(B) 2√3 cm
(C) 3√3 cm
(D) 4√3 cm
9. If A ABC - ADEF such that AB = 12 cm and DE = 14 cm. Find the ratio of areas of A ABC
and A DEF.
(A) 49/9
(B) 36/49
(C) 49/16
(D) 25/49
(2)
10. Two isosceles triangles have equal angles and their areas are in the ratio 16:25. The ratio of
corresponding heights is:
(A) 4:5
(B) 5:4
(C)3:2
(D) 5:7
=​

Answer 1

Answer:

8=C

10=A

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