Question

2.80 Rail road car A of mass 25 Mg moving with a speed of 0.5 m/s collides with car B of
mass 40 Mg at rest. After the impact cars A and B move to the right with a speed
of 0.02 m/s and 0.3 m/s respectively. Find co-efficient of restitution
(a) 0.56 (b) Q.65
(c) 0.55
(d) 0.66
Ans.: (a)​

Answer 1

Answer:

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Answer 2

Given;-

u1 = 0.5 m/s
u2 = 0 m/s

v1 = 0.02 m/s
v2 = 0.3 m/s

To Find;-

co-efficient of restitution (e)

Solution;-

Velocity of approach = u1 - u2 = 0.5 m/s = vᵇ

Velocity of separation = v2 - v1 = 0.28 m/s = vᵃ

e = $\frac{v^{a} }{v^{b} }$ = $\frac{0.28}{0.5}$ = 0.56

Hence, the co-efficient of restitution = 0.56 which is Option (a)