Question

2.82g of glucose is dissolved in 30g of water .Calculate the mole farction of glucose in the solution

Answer 1

Answer:

=0.9907

Explanation:

We know that,

The weight of glucose=2.82g

Also,

no. of moles of glucose=n

2

=

180

2.82

=0.01567

no. of moles of N

2

O=n

1

=

18

30

=1.667

Molality=

n

1

n

2

×

m.wtofsolvent

1000

=

1.667

0.01567

×

18

1000

=0.5222molal

We have moles of glucose (x

2

)=0.01567

moles of H

2

O(x

1

)=1.667

So, mole fraction of glucose

x

2

=

n

1

+n

2

n

2

=

(1.667+0.01567)

0.0157

=0.0093

mole fraction of H

2

O=x

1

x

1

=1−x

2

=1=0.0093

x

1

=0.9907