Question

2.84mL of “Chamber's acid” is made up of a litre solution. 50mL of this solution neutralize 38.2mL of N/10 Na2CO3 solution. Find the percentage of sulphuric acid in the “Chamber acid”, if its specific gravity is 1.71. [Ans: 77.08%]​

Answer 1

Answer:

also and ans 78

Explanation:

please Mark me brainly

Answer 2

Answer:given

Volume of chamber acid(Va)=2.84ml

Volume of diluted solution(V)=1L=1000ml

Now,for nutealization

of (diluted solution). With(Na2Co3)

Volume of acid solution taken(V’)=50ml.  Normality of base(Nb)=N/10

Normality of acid solution(N)=? Volume of base(Vb)=38.2ml

From principle of volumetric analysis,

NV’=NbVb

N=(NbVb)/V’

∴N=(1/10×38·2)/50=0.0764N

Then,

VaNa=NV

Na=(NV)/Va

∴Na=(0.0764×1000)/2.84=26.90N

so, we have

Normality(Na)=[(%w/w)×10×d]/E

(%w/w)=(Na×E)/(10×d)

∴(%w/w)=(26.90×49)/(10×1.71)=77.08%(Ans)

Explanation: