Question

2.8g वजन वाले लोहे के टुकड़े में आयरन के परमाणुओं की संख्या
होती है
(A) 3011x 1024 परमाणु (B) 3.011x1021 परमाणु
(C) 3.011x1022 परमाणु (D) 3.011x1023 परमाणु​

Answer 1

I didn't understand your language........

Answer 2

Explanation:

Given Number of iron atoms in a piece of iron weighing 2.8 g

• According to mole concept we have
• One mole of element = gram atomic mass of that atom.-----------------1
• One mole of element = 6.022 x 10^23 atoms (Avagadro number)-------2
• From 1 and 2 we get
• Gram atomic mass of atom = 6.022 x 10^23 atoms.
•     56 gram of iron atoms = 6.022 x 10^23
• Therefore 2.8 g of iron will have atoms = 6.022 x 10^23 x 2.8 / 56
•                                                               = 0.3011 x 10^23
•                                                               = 3.011 x 10^22 atoms.

Reference link will be

https://brainly.in/question/1901952

https://brainly.in/question/30770490#