2,9,28,?,126,217,344
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A special sequence of numbers is written as 2, 9, 28, 65, 126 …….Find the ratio of the 7th term to the 15th term.
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so.....
65 is the answer..............
_____________________________________________
so.....
65 is the answer..............
Answered by
16
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good afternoon__________________✌️✌️
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See the series
2, 9, 28, ___,126, 217
2 = 1^3+1 = 1 +1
9 = 2^3+1 = 8 + 1
28 = 3^3 +1 = 27+1
126 = 5^3 + 1 = 125+1
217 = 6^3 + 1 = 216 +1
So the missing number is 4^3+1 = 64+1 = 65
good afternoon__________________✌️✌️
________________________
______________________________
See the series
2, 9, 28, ___,126, 217
2 = 1^3+1 = 1 +1
9 = 2^3+1 = 8 + 1
28 = 3^3 +1 = 27+1
126 = 5^3 + 1 = 125+1
217 = 6^3 + 1 = 216 +1
So the missing number is 4^3+1 = 64+1 = 65
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