(2/9)^3*(2/9)^-6=2(2/9)^2n-1
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1, 2, 4, 3 is the sequence of the first 4 odd numbers and is a finite {1, 2, 4, 8, 16, 32, . ... A Sequence usually has a Rule, which is a way to find the value of each term.
It is Saying "starts at 3 and jumps 2 every time" is fine, but it deserves the sequence,
So a rule for {3, 5, 7, 9, ...} can be written as an equation like this: xn = 2n+1.
It is Saying "starts at 3 and jumps 2 every time" is fine, but it deserves the sequence,
So a rule for {3, 5, 7, 9, ...} can be written as an equation like this: xn = 2n+1.
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Answer:
(2/9)^3 ×(2/9)^6 = (2/9)^(2n-1)
(2/9)^3+6 = (2/9)^(2n-1)
comparing both sides, we get
3+6 =2n -1
3+6+1=2n
10/2 = n
m = 5
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