Question

(2/9)^3*(2/9)^-6=2(2/9)^2n-1

Answer 1

1, 2, 4, 3 is the sequence of the first 4 odd numbers and is a finite {1, 2, 4, 8, 16, 32, . ... A Sequence usually has a Rule, which is a way to find the value of each term.

It is  Saying "starts at 3 and jumps 2 every time" is fine, but it deserves the sequence,

So a rule for {3, 5, 7, 9, ...} can be written as an equation like this: xn = 2n+1.

Answer 2

Answer:

(2/9)^3 ×(2/9)^6 = (2/9)^(2n-1)

 (2/9)^3+6 = (2/9)^(2n-1)

comparing both sides, we get

3+6 =2n -1

3+6+1=2n

10/2 = n

m = 5