Question

(2/9)^3×(2/9)^-6=(2/9)^2x-1​

Answer 1

Step-by-step explanation:

Given:

${ (\frac{2}{9}) }^{3} \times { (\frac{2}{9} )}^{ - 6} = { \frac{2}{9} }^{2x - 1}$

${ (\frac{2}{9}) }^{3 - 6 } = { (\frac{2}{9}) }^{2x - 1}$

$because \: {a}^{n} + {a}^{m } = {a}^{m + n}$

$3 - 6 = 2x - 1$

$- 2 = 2x$

$x = - 1$