Question

2.9 g of a gas at 95 °C occupied the same volume
as 0.184 g of Dihydrogen at 17 °C, at the same
pressure. What is the molar mass of the gas ?​

Answer 1

Answer:

Explanation:

For gas w=2.9gT =95+273=368Kw=2.9gT=95+273=368K

For H2:w=0.184g,T=17+273=290KH2:w=0.184g,T=17+273=290K

Since VH2=Vg,PH2=PgVH2=Vg,PH2=Pg

ngTg=nH2TH2ngTg=nH2TH2

2.9m×368=0.1842×2902.9m×368=0.1842×290

or m=40mo1−1m=40mo1-1 .