Math, asked by chaahatagarwal16, 5 months ago

2/9 of the people in a restaurant are adults. If there are 95 more children than adults , how many people are there in the restaurant?

Answers

Answered by Feirxefett
3

Answer: There are 133 children in the restaurant.

Explanation:

Let the number of total children in the restaurant be x

Since we have given that

Number of adult people is given by

\frac{2}{9}x92x

So, the number of children be

1-\frac{2x}{9}=\frac{7}{9}x1−92x=97x

So,

According to question,

\begin{gathered}\frac{7x}{9}-\frac{2x}{9}=95\\\\\frac{5x}{9}=95\\\\x=\frac{95\times 9}{5}\\\\x=171\end{gathered}97x−92x=9595x=95x=595×9x=171

Hence, there are 171 people in the restaurant.

Thus, number of children in the restaurant is given by

\begin{gathered}\frac{7}{9}\times 171\\\\=19\times 7\\\\=133\end{gathered}97×171=19×7=133

So, there are 133 children in the restaurant.

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