2/9 of the people in a restaurant are adults. If there are 95 more children than adults , how many people are there in the restaurant?
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Answer: There are 133 children in the restaurant.
Explanation:
Let the number of total children in the restaurant be x
Since we have given that
Number of adult people is given by
\frac{2}{9}x92x
So, the number of children be
1-\frac{2x}{9}=\frac{7}{9}x1−92x=97x
So,
According to question,
\begin{gathered}\frac{7x}{9}-\frac{2x}{9}=95\\\\\frac{5x}{9}=95\\\\x=\frac{95\times 9}{5}\\\\x=171\end{gathered}97x−92x=9595x=95x=595×9x=171
Hence, there are 171 people in the restaurant.
Thus, number of children in the restaurant is given by
\begin{gathered}\frac{7}{9}\times 171\\\\=19\times 7\\\\=133\end{gathered}97×171=19×7=133
So, there are 133 children in the restaurant.
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