Question

2.9. The present age of father is four times the age
of his son. After 10 years, age of father will
become three times the age of his son. Find
their present ages.​

Answer 1

Answer:

The present age of father = 80

The present age of son= 20

Step-by-step explanation:

Let the age of father be 'F' and age of son be 'S'

According to question-:

Age of father is four times the age of his son.

F=4S [eq.1]

After 10 years Condition-:

Age of father will become three times the age of his son.

F+10=3(S+10) [eq.2]

10 come here because the condition is after 10 years.✓✓✓

Now, Substituting F=4S in eq.2

we get,

=> 4S+10=3S+30

=> [S=20]✓✓✓✓✓

Substituting S=20 in eq.1

we get,

F=4*20

F=80

Answer 2

Let son's age is = x

than father's age is =4x

AFTER 10 YEAR

father will be 3 times than him

According to question

4x+10= 3 (x+10)

4x+10=3x+30

4x- 3x=30-10

x=20

therefore son's present age is 20

and father's present age is 80