Question

2.9 When brakes are applied, the
96 kmh' to 48 kmh in 800 m.
move before coming to rest?
(Assuming the retardation to be
constant).

2.10 In the above problem, find the
time taken by the train to stop
after the application of brakes.​

Answer 1

Answer:

Given:-

Initial velocity (u) = 48km/hr = 13.3333m/s

Final velocity (v) = 96km/hr = 26.6667m/s

Distance (S) = 800m

By applying, v^2-u^2 = 2as

711.11288889 - 177.77688889 = 2×a×800

533.336 = 1600a

a = 0.333335m/s^2.

By applying, v - u = at

26.6667 - 13.3333 = 0.333335t

13.3334 = 0.333335t

t = 40sec.