2.93bar in the form of p÷q
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52
2.93BAR
LET X=2.93BAR
10X=29.393BAR
100X=293.93BAR
NOW WE WILL SUBTRACT THE FIRST EQUATION FROM THIRD EQUATION
100X=293.93BAR
X= 2.93BAR
99X=291.00BAR
IT CAN ALSO BE WRITTEN LIKE
X=291/99
LET X=2.93BAR
10X=29.393BAR
100X=293.93BAR
NOW WE WILL SUBTRACT THE FIRST EQUATION FROM THIRD EQUATION
100X=293.93BAR
X= 2.93BAR
99X=291.00BAR
IT CAN ALSO BE WRITTEN LIKE
X=291/99
Answered by
10
2.93BAR
LET X=2.93BAR
10X=29.393BAR
100X=293.93BAR
NOW WE WILL SUBTRACT THE FIRST EQUATION FROM THIRD EQUATION
100X=293.93BAR
X= 2.93BAR
99X=291.00BAR
IT CAN ALSO BE WRITTEN LIKE
X=291/99
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