Question

2+9t^2 ÷ 3

explain procedure to get answer = 6t ​

Answer 1

Let,

$y = \frac{2 + 9 {t}^{2} }{3} \\ \\ = > y = 3 {t}^{2} + \frac{2}{3}$

Differentiate w. r. t. t both the sides :

$\frac{dy}{dt} = 3 \times 2t + 0 \\ \\ = > \frac{dy}{dt} = 6t$

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