2-9x/16 + 5x = 0 ????????
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Answered by
2
2 - 3x/16 + 5x= 0
(32 -9x+80x) /16= 0
32 - 9x + 80x = 0x16
32 - 71x =0
71x= - 32
x = -32/71
(32 -9x+80x) /16= 0
32 - 9x + 80x = 0x16
32 - 71x =0
71x= - 32
x = -32/71
Answered by
2
2 - 9x / 16 + 5x = 0
(32 - 9x + 80x ) / 16 = 0
32 -9x + 80x = 0 × 16
32 - 71x = 0
71x = -32
x = -32/71 ( Ans )
(32 - 9x + 80x ) / 16 = 0
32 -9x + 80x = 0 × 16
32 - 71x = 0
71x = -32
x = -32/71 ( Ans )
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