Question

2. A 0.43 kg soccer ball is stationary on the field when Darryl kicks it. Darryl's foot is in
contact with the ball for 0.01 s during the kick. The horizontal velocity of the ball as it leaves
his foot is 25 m/s. What is the average horizontal force exerted by Darryl's foot on the ball
during the 0.01 s of contact (assume that friction between the ball and the field is zero)?

Answer 1

Answer:

1075 N

Explanation:

as we know there is a formula

force× time of contact= Mass × change in velocity

so F=(43/100)×25/0.01

and answer comes to be 1075