Math, asked by musleuddinsk49, 11 months ago

2 ( a^ 2+ 1\ a^2) –( a– 1\a ) –7 ( faterise)

Answers

Answered by Anonymous

Answer:

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Answer: a = 2/3 ; a = -1/2

Step-by-step explanation:

2[(a^2+1)/a^2] - [(a-1)/a] -7 = 0

(2a^2+2-a^2+a) / a^2 = 7

a^2 + a + 2 = 7a^2

a+2 = 6a^2

6a^2 - a - 2 = 0

6a^2 + 3a - 4a - 2 = 0

0= 3a(2a+1) - 2(2a+1)

0= (3a-2) (2a+1)

0= 3a-2 \ 0= 2a+1

2= 3a \ 2a= -1

a=2/3 \ a = -1/2

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Answered by gauribh42

Answer:

(2a⁴-a³-7a²+3)/a²

Step-by-step explanation:

Hope it helps you

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2 ( a^ 2+ 1\ a^2) –( a– 1\a ) –7​ ( faterise)

Answers

2 ( a^ 2+ 1\ a^2) –( a– 1\a ) –7 ( faterise)