Math, asked by himanshuhjagtap, 1 month ago

,2
A(2, 3)
3
C
B
C(-2, 2)
1
T 2 3
-3-2-10
1
Activity:
In the figure, seg AB | Y-axis and
seg CB X-axis. Co-ordinates of
points A and Care given
To find AC, fill in the boxes given below.
A ABC is a right angled triangle.
X
According to Pythagoras theorem,
(AB) + (BC)=
We will find co-ordinates of point B
to find the lengths AB and BC,
CB|| X-axis .. y co-ordinate of B=0
BA || Y-axis ... co-ordinate of B =
AB= (3-0=0
=D
..AOO+0=0 .*. AC =
3
Y
Fig. 5.6
BC =
4
V17​

Answers

Answered by meenu1251
0

,2

A(2, 3)

3

C

B

C(-2, 2)

1

T 2 3

-3-2-10

1

Activity:

In the figure, seg AB | Y-axis and

seg CB X-axis. Co-ordinates of

points A and Care given

To find AC, fill in the boxes given below.

A ABC is a right angled triangle.

X

According to Pythagoras theorem,

(AB) + (BC)=

We will find co-ordinates of point B

to find the lengths AB and BC,

CB|| X-axis .. y co-ordinate of B=0

BA || Y-axis ... co-ordinate of B =

AB= (3-0=0

=D

..AOO+0=0 .*. AC =

3

Y

Fig. 5.6

BC =

4

V17

Answered by zeenishyasir
0

Answer:

You can also use the Google

Step-by-step explanation:

1

Activity:

In the figure, seg AB | Y-axis and

seg CB X-axis. Co-ordinates of

points A and Care given

To find AC, fill in the boxes given below.

A ABC is a right angled triangle.

X

According to Pythagoras theorem,

(AB) + (BC)=

We will find co-ordinates of point B

to find the lengths AB and BC,

CB|| X-axis .. y co-ordinate of B=0

BA || Y-axis ... co-ordinate of B =

AB= (3-0=0

=D

..AOO+0=0 .*. AC =

3

Y

Fig. 5.6

BC =

4

V17

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