Question

(2-a) ^2+6a(2-a)
factorise this expression

Answer 1

(2-a)^2 + 6a(2-a)

Taking Common,

(2-a) [(2-a)  + 6a]

(2-a) [2-a+6a]

(2-a) [2+5a]

= 4 + 10a - 2a - 5a^2

4+ 8a - 5a^2



OR


(2-a)^2 + 6a(2-a)

By formula (a-b)^2 = a^2 + b^2 -2ab

4 + a^2 - 4a + 12a -6a^2

4 - 5a^2 + 8a



i hope this will help you



-by ABHAY

Answer 2

Hey !!!

(2 - a)² + 6a(2-a)

=> 2² + a² - 2×2×a + 12a -6a²

=> 4 + a² - 4a + 12a - 6a²

=> a² - 6a²+ 8a +4

=> -5a² + 8a +4

=> -5a² + 10a - 2a + 4

=> -5a(a - 2) -2 (a - 2)

=> (-5a - 2) ( a - 2) is factor of this equation

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Hope it helps you !!!

@Rajukumar111