Question

2.
a ² +8a + 16 please factorise the question​

Answer 1

Answer:

a²+8a+16

a²+4a+4a+16

a(a+4)+4(a+4)

(a+4)(a+4)

∴(a+4)²

Answer 2

$\boxed{ \underline{ \red{ \sf \: AnswEr:-}}}$

$= {(a + 4)}^{2}$

★ Given:-

• a² +8a + 16

★ To Find :-

• Factorisation

Step-by-step explanation:

$\sf \: {a}^{2} + 8a + 16$

$\implies \sf \: {a}^{2} + (4 + 4)a + 16$

$\implies \sf \: {a}^{2} + 4a + 4a + 16$

$\implies \sf \: a(a + 4) + 4(a + 4)$

$\implies \sf \: (a + 4)(a + 4)$

It can be written as,

$\implies \sf \: {(a + 4)}^{2}$

★ Process:-

• In order to factorize a² +8a + 16, we have to find two numbers p and q such that p + q = 8 and pq = 16.
• Clearly, (4+4) = 8 and (4×4) = 16.
• So we write the middle term 8a as 4a + 4a.
• By calculating next steps we can get the answer.

★ Quadratic Polynomials :-

• A polynomial of degree 2 is known as a quadratic polynomial.
• In general, f(x) = ax² + bx + c, (a is not equal to 0)
• A quadratic polynomial may be a monomial or a binomial or a trinomial.