Question

2(a^2+b^2) =(a+b) ^2​

Answer 1

HERE IS UR ANSWER DEAR,

$2( {a}^{2} + {b}^{2} ) = {(a + b)}^{2}$

$2 {a}^{2} + 2 {b}^{2} = {a}^{2} + 2ab + {b}^{2}$

because ,

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

$2 {a}^{2} + 2 {b}^{2} - {a}^{2} - {b}^{2} = 2ab$

${a}^{2} + {b}^{2} = 2ab$

${a}^{2} + {b}^{2} - 2ab = 0$

${(a - b)}^{2} = 0$

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