Question

2. A
(2)
Find the value of the discriminant of the following equation 10x +x=1
(Answer: 41)
real and equal, find the​

Answer 1

Step-by-step explanation:

11x-1=0

a=0 , b= 11 , c=-1

D=B^2-4AC

= 11^2-4×0×(-1 )

=121-0

=121

DISCRIMINANT= 121

Answer 2

Answer:

A quadratic equation in a variable xx is an equation which is of the form ax^2 + bx + c = 0ax

2

+bx+c=0 where constants a, b and c are all real numbers and a \neq 0.a



=0.

In case of a quadratic equation ax^2 + bx + c = 0ax

2

+bx+c=0 the expression b^2 - 4acb

2

−4ac is called the discriminant.

Let's first solve the given equation!

\begin{gathered}\implies 10x^2 + x = 1 \\ \\ \implies 10x^2 + x - 1 = 0\end{gathered}

⟹10x

2

+x=1

⟹10x

2

+x−1=0

Now, comparing the given equation with the standard form of quadratic equation, we get:

\qquad a = 10, \: b = 1, \: c = -1a=10,b=1,c=−1

Now using the discriminant formula and solving the equation, we get:

\begin{gathered} \implies {1}^{2} - 4 \times 10 \times (-1) \\ \\ \implies 1 - 4 \times 10 \times (-1) \\ \\ \implies 1 - (-40) \\ \\ \implies 1 + 41 \\ \\ \implies \boxed{41}\end{gathered}

⟹1

2

−4×10×(−1)

⟹1−4×10×(−1)

⟹1−(−40)

⟹1+41

⟹

41

Hence, the required answer is 41.