Math, asked by sanchit123463, 1 year ago

2. a^2*x^2+ (ax^2+ 1) x + a
(factorise by grouping method)

Answers

Answered by ihrishi
2

Answer:

 {a}^{2}  {x}^{2}  + (a {x}^{2}  + 1)x + a \\  = {a}^{2}  {x}^{2}  + a {x}^{3}  + x + a \\  = ({a}^{2}  {x}^{2}  + a {x}^{3})  +( x + a ) \\  = a {x}^{2} (a + x) + 1(x + a) \\  = (x + a)(a {x}^{2}  + 1)

Answered by sejal2251
0

Answer:

a^2*x^2+(ax^2+1)x+a

= a^2 x^2+(ax^3+1)

=a^2 x^2+ax^3+x+a

=(a^2 x^2+ax^3)+(x+a)

=ax^2(a+x) +1(x+a)

=(x+a) (ax^2+1)

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