2^a=3^b=6^-c find ab+bc+ca
Attachments:

Answers
Answered by
1
Answer:
ab+bc+ca=0
Step-by-step explanation:
Here 2^a = 6^-c
2 = 6^(-c/a)============(1)
also 3^b=6^-c
3 = 6^(-c/b)============== (2)
so 2 * 3 = 6^(-c/a - c/b)
6^1=6^(-c/a - c/b)
so 1 = - c/a - c/b=-c(1/a+1/b)
-c(a+b) /ab=1
-ca-cb=ab
or
ab+bc+ca=0
Similar questions