Question

2^a=3^b=6^-c find ab+bc+ca​

Answer 1

Answer:

ab+bc+ca=0

Step-by-step explanation:

Here 2^a = 6^-c

2 = 6^(-c/a)============(1)

also 3^b=6^-c

3 = 6^(-c/b)============== (2)

so 2 * 3 = 6^(-c/a - c/b)

6^1=6^(-c/a - c/b)

so 1 = - c/a - c/b=-c(1/a+1/b)

-c(a+b) /ab=1

-ca-cb=ab

or

ab+bc+ca=0