2^a=3^b=6^c.
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2^a = 3^b = 6^c
2^a = 6^c = 2^c*3^c
so 2^(a-c) = 3^c ....1
2^a = 3^b
so 2 = 3^(b/a) ...2
put (2) in 1
so 3^(b/a)(a-c) = 3^c
or b/a(a-c) = c
or b(a-c) = ac
or b = ac/(a-c)
if you want c i terms os a and b
ab -bc = ac
ab = c(a+b) or c = ab/(a+b)
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