Question

2^a=3^b=6^c, then c=?​

Answer 1

Answer:

Step-by-step explanation:

Let 2^a=3^b=6^c =k  

2 = k^(1/a), 3 = k^(1/b) and 6= k^(1/c)  

2*3=6  

k^(1/a)*k^(1/b) = k^(1/c)  

k^(1/a +a/b)= k^(1/c)  

1/a +a/b = 1/c  

a+b/ab = 1/c