2^a=3^b=6^c value of c ??????????????????
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Given, 2^a = 3^b = 6^c
It can be written as,
2 = 6^(c/a) and 3 = 6^(c/b)
On multiplying both, we get
6 = 6^( c/ a+ c/b)
1 = c/a + c/b
1 = c(1/a + 1/b)
= c(a+b)/(ab)
c = ab/(a+b)
Hope this helps!
It can be written as,
2 = 6^(c/a) and 3 = 6^(c/b)
On multiplying both, we get
6 = 6^( c/ a+ c/b)
1 = c/a + c/b
1 = c(1/a + 1/b)
= c(a+b)/(ab)
c = ab/(a+b)
Hope this helps!
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