Question

2^a×3^b×7^c=1176 then find a^a×b^b×7^-c​

Answer 1

Answer:

27/49

Step-by-step explanation:

2^a *3^b*7^c = 1176 --- eq1

By prime factorisation of 1176 , we get

2*2*2*3*7*7=1176

2^3*3^1*7^2=1176 ---eq2

BY COMPARING EQUATION 1 WITH EQUATION 2 :-

a=3 ; b=1;c=2

now, -c= -2

PUTTING THE VALUES OF a , b, c in given equation :-

a^a * b^b *7^-c

3^3 *1^1 *7^-2= 27*1*1/49

27/49

Answer 2

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