Question

2. A 6 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 30 cm. If distance of object from the mirror is 40 cm. Find

a) Position

b) Nature

c) Sixe of the image formed.​

Answer 1

Answer:

b) Nature is correct answer

Answer 2

Explanation:

Hint: We will start with deducing the lens formula and substituting the focal length and object distance which is provided in the question. By using the lens formula we find the image distance. By using the magnification formula of the lens we will find the size, nature, and position of the image formed.

Formula used

⇒1v−1u=1f

Complete solution:

Now for the image distance, we will use the lens formula. Lens formula shows the relationship between the image distance (v), object distance (u), and focal length (f).

⇒1v−1u=1f ------------ Equation (1)

Now substituting the value of object distance (v), the focal length (f) in the lens formula in the Equation (1)

⇒u=10cm

⇒f=15cm

Now after substitution

⇒1v−1−10=115

⇒1v=115+1−10

⇒1v=115−110

⇒1v=10−15150

⇒1v=−5150

Now rearranging the values we get,

⇒v=−1505

∴v=−30cm

Hence the image distance v=−30cm

The negative sign of the image distance (v) shows that the image is on the same side of the lens.

Now by using magnification (m)

⇒magnification(m)=hih=vu

Where hi is the height of the image and the h is object height