2) A and B can do a piece of work in 25 days
and B can do same work in 50 days. In how
many days will A alone can do the same
piece of work?
Answers
Answered by
1
Answer:
Time taken to do a piece of work of A and B = 25 days
Time taken to do same work by B = 50 days
Time taken to do the work by A = 25/50
= 1/10 days Answer
Answered by
0
A can do in 50 days
Step-by-step explanation:
A+B FULL WORK IN DAY = 25 DAYS
B CAN DO SINGLE IN =50 DAYS
WORK OF B IN ONE DAY = 1/50 DAYS
LET'S A FINISH WORK = X DAYS
WORK OF A DONE IN ONE DAY = 1/x
WORK OF A+B IN ONE DAY = 1/x + 1/50
= 50+x / 50x
ACCORDING TO QUESTION
WORK OF A + B = 1/25 days
= 50 + x / 50x = 1/25
= 50x = 25 (50+x)
2x = 50 + x
2x - x = 50
x = 50 days
SO A DO WORK IN 50 DAYS
PLEASE LIKE IF YOU UNDERSTAND
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