Question

2. A and B together can do a piece of work in 15 days. If A's one day's work is 1 1/2 then one
day's work of B, in how many days can each do the work​

Answer 1

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A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15

If A alone can complete a work in 20 days then A's one day work =1/20

Let B alone can complete the work in x days , so B's one day work = 1/x

NOW,

(A+B)’s one day work = A’s one day work + B’s one day work

=> 1/15=1/20+1/x

=> 1/x= 1/15 - 1/20

=> 1/x = 1/60

Hence B alone can complete the work in 60 days

Answer 2

Answer:

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/x

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,(A+B)’s one day work = A’s one day work + B’s one day work

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,(A+B)’s one day work = A’s one day work + B’s one day work=> 1/15=1/20+1/x

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,(A+B)’s one day work = A’s one day work + B’s one day work=> 1/15=1/20+1/x=> 1/x= 1/15 - 1/20

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,(A+B)’s one day work = A’s one day work + B’s one day work=> 1/15=1/20+1/x=> 1/x= 1/15 - 1/20=> 1/x = 1/60

A and B together can complete the work in 15 days, so (A+B)’s one day work = 1/15If A alone can complete a work in 20 days then A's one day work =1/20Let B alone can complete the work in x days , so B's one day work = 1/xNOW,(A+B)’s one day work = A’s one day work + B’s one day work=> 1/15=1/20+1/x=> 1/x= 1/15 - 1/20=> 1/x = 1/60Hence B alone can complete the work in 60 days

Step-by-step explanation:

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